QuickMath will automatically answer the most common problems in algebra, equations and calculus faced by high-school and college students. The algebra section allows you to expand, factor or simplify virtually any expression you choose. It also has commands for splitting fractions into partial fractions, combining several fractions into one and Explanation. (1) Multiply both sides of the equation by the common denominator: \dfrac {a \times 3} {3} = 4 a \times 3 - 33 \times 3 3aÃ3 =4aÃ3â33Ã3. Reduce the fractions: a = 4 a \times 3 - 33 \times 3 a=4aÃ3â33Ã3. Multiply the monomials: a = 12 a - 33 \times 3 a= 12aâ33Ã3. Calculate the product or quotient: a = 12 a - 99 a= 12aâ99. Which of the following demonstrates the Commutative Property of Multiplication? 3(4a â 2) = 12a â 6 3(4a â 2) = (4a â 2) â 3 12a â 6 = (4a â 2) â 3 (3 â 4a) â 2 = 3(4a â 2) verified. Verified answer. Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice as old as his sister, how old is Jennifer Two numbers r and s sum up to \frac{4}{3} exactly when the average of the two numbers is \frac{1}{2}*\frac{4}{3} = \frac{2}{3}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. Free Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators step-by-step Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Solve for a -2/3a+3=-a-2+3/4a. Step 1. Since is on the right side of the equation, switch the sides so it is on the left side of the equation. Step 2. Simplify . Tap for more steps Step 2.1. Combine and . Step 2.2. To write as a fraction with a common denominator, multiply by . Step 2.3. Simplify terms. Tap for more steps 2 This gives us 3

ln â¡ (4 a) 3\ln (4a) 3 ln (4 a) 3 Apply the product rule of logarithms, which states that ln One solution was found : a = 29/9 = 3.222. Learn with Tiger how to do 3 (a-2/3)=3/4a+21/4 fractions in a clear and easy way : Equivalent Fractions,Least Common Denominator, Reducing (Simplifying) Fractions Tiger Algebra Solver. Multiply a2 a 2 by a3 a 3 by adding the exponents. Tap for more steps 4a5 16b(b2) 4 a 5 16 b ( b 2) Multiply b b by b2 b 2 by adding the exponents. Tap for more steps 4a5 16b3 4 a 5 16 b 3. Cancel the common factor of 4 4 and 16 16. Tap for more steps a5 4b3 a 5 4 b 3. To find the opposite of 4a^{4}+12a^{3}+4a^{2}+16, find the opposite of each term. 4-12a^{3}-4a^{2}-16 . Combine 4a^{4} and -4a^{4} to get .-12-12a^{3}-4a^{2} Subtract 16 from 4 to get -12. 4a^{4}+4-\left(4a^{2}-4a+4\right)\left(a^{2}+4a+4\right) Use the distributive property to multiply 4 by a^{4}+1. Remove the absolute value term. This creates a ± ± on the right side of the equation because |x| = ±x | x | = ± x. 3 4aâ3 = ±9 3 4 a - 3 = ± 9. The complete solution is the result of both the positive and negative portions of the solution. Tap for more steps a = 16,â8 a = 16, - 8. Free math problem solver answers your algebra Mathematics professor at Community Colleges. To do this problem, always think of use distributive law twice. ( 4a -3 ) ( 4a+3) = (4 a +3 ) 4a - 3 (4a +3) =. 16a 2 + 12a - 12a - 9 = 16a 2 -9. This way of thinking of use of distributive law will be very useful . (X + a ) ( X+b ) = X ( X +a ) + b ( X + a) = X 2 + aX + bX +ab = X 2 + ( a +b) X + ab. Here 3 is multiplied inside the parenthesis. Distributive property is applied. is same as . Here, the terms 3 and 4a-2 are interchanged. So this equation demonstrates the commutative property of multiplication. GCF 3 is factored out. factoring is applied. Here 3 is not a common factor. Quotient : 4a 2 +4a+1 Remainder: 0 . Trying to factor by splitting the middle term 2.3 Factoring 4a 2 +4a+1

The first term is, 4a 2 its coefficient is 4 . The middle term is, +4a its coefficient is 4 . The last term, "the constant", is +1 Step-1 : Multiply the coefficient of the first term by the constant 4 ⢠1 = 4 Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. substitute this value into the left side of the equation and if equal to the right side then it is the solution. (4 Ã3) +(3 Ã4) = 12 +12 = 24 = right side. â a = 3 is the solution. Answer link. a=3 "distribute bracket and collect like terms on left side" 4a+3a+3=24 rArr7a+3=24 "subtract 3 from both sides" 7acancel (+3)cancel (-3)=24-3 â (4a) 3 + (3b) 3. â (4a + 3b) ((4a) 2 - 12ab + (3b) 2) â 5 à 7 (From 1 and 2) = 35. â´ The value of (64a 3 + 27b 3) is 35. Download Solution PDF. If the position of the last 2 digits of a 3 digit number are inter-changed, the new number thus created is 54 higher than the original number. What is the difference between the last two c = -1 Explanation: The first step is to distribute the brackets. hence: 4c - 4 = -6c - 12 +2c Now collect the terms in c to the left side and collect numeric terms on the right. Basic Math. Solve for a 4a^4=8a^3+4a^2. 4a4 = 8a3 + 4a2 4 a 4 = 8 a 3 + 4 a 2. Since a a is on the right side of the equation, switch the sides so it is on the left side of the equation. 8a3 + 4a2 = 4a4 8 a 3 + 4 a 2 = 4 a 4. Subtract 4a4 4 a 4 from both sides of the equation. 8a3 + 4a2 â4a4 = 0 8 a 3 + 4 a 2 - 4 a 4 = 0. a, 2a + 1, 3a + 2, 4a + 3, verify that the following is an AP, and then write its next three terms. Solution: An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term. aâ = a. aâ = 2a + 11. aâ = 3a + 21. aâ = 4a + 3 Step-by-step explanation: 4 (a + 3) = 12 + 4a.

Start by distributing 4 inside the parentheses. This means to multiply everything inside the parentheses by 4. 4a + 12= 12 + 4a. Already, you can see that they are exactly the same (if you switch the terms around), but we can continue to make sure. Subtract 4a from both sides of the equation. 12 = 12. To solve 4(a + 3) = 12 + 4a requires us to find the value of 'a'. To solve the equation, we start by expanding the left side: 4a + 12 = 12 + 4a. Next, we can subtract 4a from both sides of the equation: 4a + 12 - 4a = 12 + 4a - 4a. Which simplifies to: 12 = 12. This equation shows that 'a' can be any real number and the equation will still hold