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QuickMath will automatically answer the most common problems in algebra, equations and calculus faced by high-school and college students. The algebra section allows you to expand, factor or simplify virtually any expression you choose. It also has commands for splitting fractions into partial fractions, combining several fractions into one and Remove the absolute value term. This creates a ± ± on the right side of the equation because |x| = ±x | x | = ± x. 3 4a−3 = ±9 3 4 a - 3 = ± 9. The complete solution is the result of both the positive and negative portions of the solution. Tap for more steps a = 16,−8 a = 16, - 8. Free math problem solver answers your algebra Explanation. (1) Multiply both sides of the equation by the common denominator: \dfrac {a \times 3} {3} = 4 a \times 3 - 33 \times 3 3a×3 =4a×3−33×3. Reduce the fractions: a = 4 a \times 3 - 33 \times 3 a=4a×3−33×3. Multiply the monomials: a = 12 a - 33 \times 3 a= 12a−33×3. Calculate the product or quotient: a = 12 a - 99 a= 12a−99. Free Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators step-by-step Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Algebra. Solve for a a^3-4a^2+4a=0. a3 − 4a2 + 4a = 0 a 3 - 4 a 2 + 4 a = 0. Factor the left side of the equation. Tap for more steps a(a−2)2 = 0 a ( a - 2) 2 = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. a = 0 a = 0. (a−2)2 = 0 ( a - 2) 2 = 0. Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Solve Quadratic Equation by Completing The Square. 5.2 Solving a2-4a+4 = 0 by Completing The Square . Subtract 4 from both side of the equation : a2-4a = -4. Now the clever bit:
Take the coefficient of a , which is 4 , divide by two, giving 2 , and finally square it giving 4. Add 4 to both sides of the equation : 3.1 Find roots (zeroes) of : F (a) = a4-4a3+6a2-4a+1. Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F (a)=0. Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers. 3-Digit Subtraction Using Place Value Disks — Interactive Slides Practice subtracting multiples of 100 using place value disks with an interactive drag-and-drop activity. Slide Grade 3 Plus Plan Addition and Subtraction with Regrouping - Posters Break down the steps to use regrouping to find a solution with an addition and a subtraction First you take the first part of the first expression (4a) times the first part of the second expression, which also happens to be (4a). Your answer to this part of the problem is 16a 2. Next, you deal with the middle term. In this case the middle term of the expanded equation is determined by the (-3) in the first binomial and the (4a) in the See the entire solution process below: Explanation: To put this expression in the standard form multiply these two terms by multiplying each individual term in the left parenthesis by each individual 1 Answer. Distribute the a into the parentheses. 4a2 +3a. Distributing a (multiplying a to what is inside the parentheses) will result in. 4a ×a +3 × a = 4a2 + 3a. Solve for a -2/3a+3=-a-2+3/4a. Step 1. Since is on the right side of the equation, switch the sides so it is on the left side of the equation. Step 2. Simplify . Tap for more steps Step 2.1. Combine and . Step 2.2. To write as a fraction with a common denominator, multiply by . Step 2.3. Simplify terms. Tap for more steps Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and
more. What are the factors? A factor is a number that divides another number, leaving no remainder. In other words, if multiplying two whole numbers gives us a product, then the numbers we are multiplying are factors of the product because they are divisible by the product. Here given expression is . So, Hence, the option (2) is correct i.e., . substitute this value into the left side of the equation and if equal to the right side then it is the solution. (4 ×3) +(3 ×4) = 12 +12 = 24 = right side. ⇒ a = 3 is the solution. Answer link. a=3 "distribute bracket and collect like terms on left side" 4a+3a+3=24 rArr7a+3=24 "subtract 3 from both sides" 7acancel (+3)cancel (-3)=24-3 Apply the product rule to −4a3 - 4 a 3. Raise −4 - 4 to the power of 3 3. Multiply the exponents in (a3)3 ( a 3) 3. Tap for more steps Multiply a9 a 9 by a4 a 4 by adding the exponents. Tap for more steps Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by Step-by-step explanation: 4 (a + 3) = 12 + 4a. Start by distributing 4 inside the parentheses. This means to multiply everything inside the parentheses by 4. 4a + 12= 12 + 4a. Already, you can see that they are exactly the same (if you switch the terms around), but we can continue to make sure. Subtract 4a from both sides of the equation. 12 = 12. Learn how to factorise a quadratic expression using the formula and examples from Brainly.in, the largest online student community. Integration. ∫ 01 xe−x2dx. Limits. x→−3lim x2 + 2x − 3x2 − 9. Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. a = 3. Step-by-step explanation: Given : equation 4a + 3 (a + 1) = 24. We have to solve for a and choose the correct option from the given options. Consider the given equation 4a + 3 (a + 1) = 24. Multiply each term in bracket with 3, we have, 4a
+ 3a + 3 = 24. Adding 4a and 3a , we have, 7a + 3 = 24. ⇒ (4a) 3 + (3b) 3. ⇒ (4a + 3b) ((4a) 2 - 12ab + (3b) 2) ⇒ 5 × 7 (From 1 and 2) = 35. ∴ The value of (64a 3 + 27b 3) is 35. Download Solution PDF. If the position of the last 2 digits of a 3 digit number are inter-changed, the new number thus created is 54 higher than the original number. What is the difference between the last two